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Wednesday, September 11, 2013

Concrete Design

1.1 TWO-WAY SLAB 1.1.2 Calculating slab thickness and the Reinforcement required: 1. declaim slab thickness [D = short clear span (Lnx) / 38] to find Self-weight S/W = D x 25 = KPa (a) find G & Q ( Assume 150mm for D if not given) (b) SERVICEABILITY: (short span) Lx = min(L, Ln + D) = in meters (long span) Ly = min(L, Ln + D) = in meters 2. Find ?L & ?s normally they argon ?L = 0.4 ?s = 0.7 4. Assume Kcs = 2 (no compression reinforcement) 5. fount formula on page 98 to check if (D) cognition is OK, only first find (dx) dx = D cover dr/2 (Assume avert Diameter if not given.
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N12 is best) (a) For the deemed to comply formula on (page 98) practise [Lef/d = Lx/dx] for both cases in instigate b) (i) & (ii) where dx = D cover dr/2 (Assume Bar Diameter. Best wiz is N12) (b) conduct attention to K 3 & K4 ! Page 99 & 100 If the slab is support on quaternity sides must check two moulding conditions: The formula on page 98 has to be utilise for both (i) & (ii) they both have Different K4 values but everything else is the same. i) Two adjacent butts discontinuous ii) whizz long edge discontinuous ----------------------If (D) is not OK estimate a invigorated bar Diameter and start Step 5 again-------------------- 6. If (D) is OK from step 5 use it as your depth...If you inadequacy to rent a full essay, order it on our website: OrderCustomPaper.com

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